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Mathematics: NTSE Number Series Practice and Concepts

NTSE math material on number series, including arithmetic and geometric progressions, mixed series, twin series, and wrong-number questions.

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TRIVENI NTSE PROGRAM Number Series 1

1 1

Mental ability is the ability to distinguish

between right and wrong, to judge the minutest

difference and to adapt to the ever changing

environment, the wit to master the situation, the

capacity to learn and to put past experience to the

most advantageous use in future and the ability to

distinguish between important, less important and

more important.

v EXAMPLES v

Completing the Given Series

Ex.1 Which number would replace question mark

in the series 7, 12, 19, ?, 39.

(A) 29 (B) 28

(C) 26 (D) 24

Sol. Clearly, the given sequence follows the

pattern:

+5, +7, +9 ... i.e., 7 + 5 = 12, 12 + 7 = 19, ...

Missing number = 19 + 9 = 28

Hence, the answer is (B).

Ex.2 Which is the number that comes next in the

sequence : 0, 6, 24, 60, 120, 210 ?

(A) 240 (B) 290 (C) 336 (D) 504

Sol. Clearly, the given series is

13 – 1, 23 – 2, 33 – 3, 43 – 4, 53 – 5, 63 – 6.

Next number = 73 – 7 = 343 – 7 = 336

Hence, the answer is (C).

Ex.3 Which is the number that comes next in the

following sequence ?

4, 6, 12, 14, 28, 30,(...)

(A) 32 (B) 60 (C) 62 (D) 64

Sol. The given sequence is a combination of two

series :

I. 4, 12, 28 (...) and II. 6, 14, 30.

Now, the pattern followed in each of the

above two series is : +8, +16, +32 ....

So, missing number = (28 + 32) = 60

Hence, the answer is (B).

Ex.4 Find out the missing number in the following

sequence : 1, 3, 3, 6, 7, 9, ?, 12, 21.

(A) 10 (B) 11 (C) 12 (D) 13

Sol. Clearly, the given sequence is a combination

of two series :

I. 1, 3, 7, ?, 21 and II. 3, 6, 9, 12

The pattern followed in I is + 2, + 4, ...; and

the pattern followed in II is +3. Thus, missing

number = 7 + 6 = 13.

Hence, the answer is (D).

Ex.5 Which fraction comes next in the sequence

, , , , ?

(A) (B) (C) (D)

1

CHAPTER

CONTENTS

Ÿ Definition

Ÿ Completing the series

Ÿ Arithmetic Series

Ÿ Series of Cubes, Squares

Ÿ Mixed Series

Ÿ Two-Tier Arithemetic series

Ÿ Three-Tier Arithemetic series

Ÿ Twin-Series

Ÿ Two line number series

Ÿ Wrong Number series

2

1

4

3

8

5

16

7

32

9

17

10

34

11

35

12

TRIVENI IIT IMPACT

NTSE - MAT MATERIAL

CHAPTER : NUMBER SERIES

TRIVENI NTSE PROGRAM Number Series 2

2 2

Sol. Clearly, the numerators of the fractions in the

given sequence form the series 1, 3, 5, 7, in

which each term is obtained by adding 2 to

the previous term. The denominators of the

fractions form the series 2, 4, 8, 16,

i.e. 21, 22, 23, 24.

So, the numerator of the next fraction will be

(7 + 12) i.e., 9 and the denominator will be 25

i.e. 32.

The next term is

Hence, the answer is (A).

Elementary Idea of Progressions

(I) Arithmetic Progression (A.P.)

The progression of the form a, a + d, a + 2d,

a + 3d, ... is known as an A.P. with first term

= a and common difference = d.

Ex. 3, 6, 9, 12, .... is an A.P. with a = 3 and

d = 6 – 3 = 3.

In an A.P., we have nth term = a + (n – 1)d.

(II) Geometric Progression (G.P.)

The progression of the form a, ar, ar2, ar3, ...

is known as a G.P. with first term = a and

common ratio = r.

Ex. 1, 5, 25, 125, ... is a G.P. with a = 1 and

r = = = ... = 5.

In a G.P. we have nth term = arn–1.

v EXAMPLES v

Ex.6 In the series 357, 363, 369, ..., what will be

the 10th term ?

(A) 405 (B) 411 (C) 413 (D) 417

Sol. The given series is an A.P. in which a = 357

and d = 6.

10th term = a + (10 – 1) d = a + 9d.

= (357 + 9 × 6) = (357 + 54)

= 411

Hence, the answer is (B).

Ex.7 How many terms are there in the series 201,

208, 215, .... 369 ?

(A) 23 (B) 24 (C) 25 (D) 26

Sol. The given series in an A.P. in which a = 201

and d = 7.

Let the number of terms be n.

Then, 369 = 201 + (n – 1) × 7 or n = 25.

Hence, the answer is (C).

Ex.8 In the series 7, 14, 28, ..., what will be the

10th term ?

(A) 1792 (B) 2456 (C) 3584 (D) 4096

Sol. Clearly, 7 × 2 = 14, 14 × 2 = 28, ... and so on.

So, the given series is a G.P. in which

a = 7 and r = 2.

10th term = ar(10–1) = ar9 = 7 × 29

= 7 × 512 = 3584

Hence, the answer is (C).

Ex.9 1, 4, 9, 16, 25, (...)

(A) 35 (B) 36 (C) 48 (D) 49

Sol. The numbers are 12, 22, 32, 42, 52

Missing number = 62 = 36

Ex.10 20, 19, 17, (...), 10, 5

(A) 12 (B) 13 (C) 14 (D) 15

Sol. The pattern is –1, –2, ...

Missing number = 17 – 3 = 14

Ex.11 2, 3, 5, 7, 11, (...), 17

(A) 12 (B) 13 (C) 14 (D) 15

Sol. Clearly, the given series consists of prime

numbers starting from 2. The prime number

after 11 is 13. So, 13 is the missing number.

Ex.12 6, 11, 21, 36, 56, (...)

(A) 42 (B) 51 (C) 81 (D) 91

Sol. The pattern is +5, +10, +15, + 20, ...

Missing number = 56 + 25 = 81

Ex.13 1, 6, 13, 22, 33, (...)

(A) 44 (B) 45 (C) 46 (D) 47

Sol. The pattern is + 5, + 7, + 9, + 11, ...

Missing number = 33 + 13 = 46

Ex.14 3, 9, 27, 81, (...)

(A) 324 (B) 243 (C) 210 (D) 162

Sol. Each term of the given series is obtained by

multiplying its preceding term by 3.

Missing number = 81 × 3 = 243

32

9

1

5

5

25

TRIVENI NTSE PROGRAM Number Series 3

3 3

Ex.15 1, 9, 17, 33, 49, 73, (...)

(A) 97 (B) 98 (C) 99 (D) 100

Sol. The pattern is +8, +8, +16, +16, +24, ...

Missing number = 73 + 24 = 97

Ex.16 2, 5, 9, (...), 20, 27

(A) 14 (B) 16 (C) 18 (D) 24

Sol. The pattern is +3, +4, ...

Missing number = 9 + 5 = 14

Ex.17 5, 9, 17, 29, 45, (...)

(A) 60 (B) 65 (C) 68 (D) 70

Sol. The pattern is +4, +8, +12, +16, ...

Missing number = 45 + 20 = 65

Ex.18 3, 7, 15, 31, 63, (...)

(A) 92 (B) 115 (C) 127 (D) 131

Sol. Each number in the series is the preceding

number multiplied by 2 and then increased by

1.

Thus, (3 × 2) + 1 = 7, (7 × 2) + 1 = 15,

(15 × 2) + 1 = 31 and so on.

Missing number = (63 × 2) + 1 = 127

Ex.19 1, 6, 15, (...), 45, 66, 91

(A) 25 (B) 26 (C) 27 (D) 28

Sol. The pattern is +5, +9, ..., +21, +25

Missing number = 15 + 13 = 28

Ex.20 1, 2, 3, 5, 8, (...)

(A) 9 (B) 11 (C) 13 (D) 15

Sol. Each term in the series is the sum of the

preceding two terms.

Thus, 1 + 2 = 3; 2 + 3 = 5; 3 + 5 = 8 and so

on.

Missing number = 5 + 8 = 13

Series

Series is a sequence of numbers obtained by

some particular predefined rule and applying

that predefined rule it is possible to find out

the next term of the series.

A series can be created in many ways. Some

of these are discussed below :

(i) Arithmetic Series.

For example,

Ø 3, 5, 7, 9, 11,......

Ø 10, 8, 6, 4, 2,......

Ø 13, 22, 31, 40, 49,.....

Ø 31, 27, 23, 19, 15,.....etc.

are arithmetic series because in each of them

the next number can be obtained by adding or

subtracting a fixed number. For example in 3,

5, 7, 9, 11,..... every successive number is

obtained by adding 2 to the previous number.

(ii) Geometric Series.

For example,

Ø 4, 8, 16, 32, 64,....

Ø 15, –30, 60, –120, 240,....

Ø 1024, 512, 256, 128, 64,....

Ø 3125, –625, 125, –25, 5,.....

are geometric series because, in each of them,

the next number can be obtained by

multiplying (or dividing) the previous number

by a fixed number. (For example, in : 3125–

625, 125, –25, 5... every successive number is

obtained by dividing the previous number by

–5.)

(iii) Series of squares, cubes :

These series can be formed by squaring or

cubing every successive number.

For example,

Ø 2, 4, 16, 256,.....

Ø 3, 9, 81, 6561,....

Ø 2, 8, 512,.... etc.

are such series. (In the first and second, every

number is squared to get the next number

while in the third it is cubed).

(iv) Mixed Series :

By a mixed series, we mean a series which is

created according to any non-conventional

(but logical) rule. Because there is no

limitation to people's imagination, there are

infinite ways in which a series can be created

and naturally it is not possible to club

together all of them.

Classification

(I) Two-tier Arithmetic Series :

In an arithmetic series the difference of any

two successive numbers is fixed. A Two-tier

Arithmetic Series shall be the one in which

the differences of successive numbers

themselves form an arithmetic series.

TRIVENI NTSE PROGRAM Number Series 4

4 4

For example,

(a) 1, 2, 5, 10, 17, 26, 37,.....

(b) 3, 5, 9, 15, 23, 33, .....etc.

are examples of such series. In 1, 2, 5, 10, 17,

26, 37, ......; for example, the differences of

successive numbers are 1, 3, 5, 7, 9, 11,

....which is an arithmetic series.

Note :

Two-tier arithmetic series can be denoted as a

quadratic function. For example, the above

series

(a) is 02 + 1, 12 + 1, 22 + 1, 32 + 1,.... which can

be denoted as f(x) = x2 + 1, where x = 0, 1,

2,.... similarly example (b) can be denoted as

f(x) = x2 + x + 3, x = 0, 1, 2, 3,.....

(II)Three-tier Arithmetic Series :

This, as the name suggests, is a series in

which the differences of successive numbers

form a two-tier arithmetic series; whose

successive term's differences, in turn, form an

arithmetic series.

For example

(a) 336, 210, 120, 60, 24, 6, 0,...

is an example of three-tier arithmetic series.

[The differences of successive terms are 126,

90, 60, 36, 18, 6,.....

The differences of successive terms of this

new series are 36, 30, 24, 18, 12,.....

which is an arithmetic series.]

Note :

Three-tier arithmetic series can be denoted as

a cubic function. For example, the above

series is (from right end) 13 –1, 23 –2, 33 –3,

43 –4, .... which can also be denoted as f(x) =

x3 –x; x = 1, 2,....

(III) Important Results

Ø In an arithmetic series we add (or deduct) a

fixed number to find the next number, and

Ø In a geometric series we multiply (or divide) a

fixed number to find the next number.

We can combine these two ideas into one to

from

(a) Arithmetico-geometric Series :

This series each successive term should be

found by first adding a fixed number to the

previous term and then multiplying it by

another fixed number.

For example

1, 6, 21, 66, 201,.........

is an arithmetico-geometric series. (Each

successive term is obtained by first adding 1

to the previous term and then multiplying it

by 3).

Note :

The differences of successive numbers should

be in Geometric Progression.

In this case, the successive differences are 5,

15, 45, 135,.... which are in G.P.

(b) Geometrico-Arithmetic Series

A geometrico-arithmetic series should be the

one in which each successive term is found

by first multiplying (or dividing) the previous

term by a fixed number and then adding (or

deducting) another fixed number.

For example

3, 4, 7, 16, 43, 124,....

is a geometrico-arithmetic series. (Each

successive term is obtained by first

multiplying the previous number by 3 and

then subtracting 5 from it.)

Note :

The differences of successive numbers should

be in geometric progression. In this case, the

successive differences are 1, 3, 9, 27, 81,

....which are in G.P.

(IV) Twin Series :

We shall call these twin series, because they

are two series packed in one.

1, 3, 5, 1, 9, –3, 13, –11, 17,.......

is an example of twin series. (The first, third,

fifth etc., terms are 1, 5, 9, 13, 17 which is an

arithmetic series. The second, fourth, sixth

etc. are 3, 1, –3, –11 which is a geometrico￾arithmetic series in which successive terms

are obtained by multiplying the previous term

by 2 and then subtracting 5.)

TRIVENI NTSE PROGRAM Number Series 5

5 5

(V) Other Series :

Besides, numerous other series are possible

and it is impossible to even think of all of

them.

SUMMARY OF THREE STEPS

[Very Important]

Step I : Do a preliminary screening of the series.

If it is a simple series you will be able to solve it

easily.

Step II : If you fail in preliminary screening then

determine the trend of the series. Determine

whether it is increasing, decreasing or alternating.

Step III (A) : Perform this step only if a series is

increasing or decreasing. Use the following rules :

(a) If the rise of a series is slow or gradual, the

series is likely to have an addition-based increase;

successive numbers are obtained by adding some

numbers.

(b) If the rise of a series is very sharp initially but

slows down later on, the series is likely to be

formed by adding squared or cubed numbers.

(c) If the rise of a series is throughout equally

sharp, the series is likely to be multiplication￾based; successive terms are obtained by

multiplying by some terms (and, maybe, some

addition or subtraction could be there, too).

(d) If the rise of a series is irregular, there may be

two possibilities. Either there may be a mix of two

series or two different kinds of operations may be

going on alternately. (The first is more likely

when the increase is very irregular : the second is

more likely when there is a pattern, even in the

irregularity of the series).

Step (III) (B) : (to be performed when the series

is alternating)

[Same as (iv) of step (iii), Check two possibilities]

Some Solved Examples

Ex. Find the next number of the series

(i) 8, 14, 26, 50, 98, 194

(ii) 8, 8, 9, 9, 11, 10, 14, 11

(iii)325, 259, 204, 160, 127, 105

(iv) 54, 43, 34, 27, 22, 19

(v) 824, 408, 200, 96, 44, 18

(vi) 16, 17, 21, 30, 46, 71

(vii) 3, 3, 6, 18, 72, 360

(viii) 3, 4, 8, 17, 33, 58

(ix) 6, 16, 36, 76, 156, 316

(x) –2, 4, 22, 58, 118, 208

Solution

(i) Sharp increase and terms roughly doubling

every time. On checking with 2 as multiple

the series is:

next term = previous term × 2 –2. Next term =

382.

(ii) Irregular. Very irregular. Likely to be,

therefore, mixed. On checking it is a mix of

two series:

8, 9, 11, 14, (+1, +2, +3 etc.) and 8, 9, 10, 11.

Next term = 14 + 4 + 18.

(iii)Gradual slow decrease. Likely to be

arithmetical decrease. Check the differences

of successive terms. They are 66, 55, 44, 33,

22. Hence, next decrease will be : 11.

Next term = 105 – 11 = 94.

(iv)Gradual slow decrease. Likely to be

arithmetical decrease. Check the differences.

They are 11, 9, 7, 5, 3. Hence, next decrease

will be 1. Next term = 19 – 1 = 18.

(v) Sharp decrease and terms roughly being

halved every time. Checking with 2 as divisor

the series is :

Next term (previous term – 8) ÷ 2.

Next term = 5.

(vi) preliminary screening tells us that each term

is obtained by adding 12, 22, 32, 42, 52......

respectively.

Next term = 71 + 62 = 107

(vii) Sharp increase. The series is : × 1, × 2, ×3,

×4, ×5, ....Next term = 360 × 6 = 2160

(viii) Sharp increase that slows down later no.

(Ratios of successive terms rise sharply from

4 ÷ 3 = 1.3 to 8 ÷ 4 = 2 to 17 ÷ 8 = 2. 125 and

then start falling to 33 ÷ 17 » 1.9 and then to

58 ÷ 33 ÷ 1.8). Hence likely to be addition of

squared or cubed numbers. On checking the

series is:

+ 12 +22, +32, +42, +52, .... Next term =

58 + 62 = 94.

TRIVENI NTSE PROGRAM Number Series 6

6 6

(ix) Sharp increase with terms roughly doubling

each time. Likely to have geometrical nature

with 2 as multiple. On checking the series is:

×2 +4. Next term = 316 × 2 + 4 = 636

(x) Series increases sharply but then its speed of

rise slows down. Likely to be addition of

squared or cubed numbers. On checking, the

series is: 13 – 3, 23 – 4, 33 – 5, 43 – 6.... Next

term = 73 – 9 = 334.

Wrong Number in Series

In examinations, a series is more likely to be

given the format of a complete series in

which an incorrect number is included & it is

required to find out the wrong number. On

studying a given series and applying the

concepts employed so far you should be able

to understand and thus "decode" the

formation of the series. Usually six terms are

given and it means that at least five correct

terms are given.

Some Unique Series

These series may be asked in examinations, so

you must be aware of them.

I. Series of Date or Time

1. Which of the following doesn't fit into the

series?

5–1–96, 27–1–96, 18–2–96, 12–3–96,

Sol. Each successive date differs by 22 days.

Recall that 96 is a leap year, you will find that

12–3–96 should be replaced by 11–3–96.

2. Which of the following doesn't fit into the

series?

5.40, 8.00, 10.20, 12.30, 3.00, 5.20

Sol. Each successive time differs by 2 hrs. 20

minutes. So 12.30 should be replaced

by 12.40.

Note : Keep in mind that the problem of series may

be based on dates or times. Sometimes it

doesn't strike our mind and the question is

solved wrongly.

II. Fractional series

Which of the following doesn't fit into the

series?

1. , , , ,

Sol. Whenever you find that most of the fractions

have the same denominators, change all the

denominators to the same value. For example,

in this question, the series becomes :

, , , ,

Now, it is clear that numerators must decrease

successively by 5. Therefore, should be

replaced by .

2. , , , , ,

Sol. By the above rule if we change all the

fractions with the same denominators, the

series is , , , , , .

We see that numerators decrease by 5, thus

should be replaced by .

Now, we conclude that the above fractions

decrease successively by or .

3 , , , , ,

Sol. We see that all the denominators differ, so we

can't use the above rule. In this case usually,

the numerators and denominators change in a

definite pattern. Here, numerators decrease

successively by 18 whereas denominators

decrease successively by 26. Thus

should be replaced by .

4. , , , , ,

Sol. Numerators increase successively by 3

whereas denominators decrease successively

by 3. Thus should be replaced by .

5

4

15

7

15

1

5

1 - 15

8 -

15

12

15

7

15

1

15

3 - 15

8 -

15

1

15

2

5

4

35

23

35

18

35

12

35

8

35

3

35

28

35

23

35

18

35

12

35

8

35

3

35

12

35

13

35

5

7

1

225

118

199

100

173

82

147

66

121

46

95

28

147

66

147

64

89

12

86

15

82

18

80

21

77

24

74

27

82

18

83

18

TRIVENI NTSE PROGRAM Number Series 7

7 7

III. Some numbers followed by their LCM or

HCF

1. 1, 2, 3, 6, 4, 5, 6, 60, 5, 6, 7,..... (Fill up the

blank)

Sol. The series can be separated in three parts. 1,

2, 3, 6/4, 5, 6, 60/5, 6, 7..... In each part fourth

number is LCM of first three

2. 8, 6, 24, 7, 3, 21, 5, 4, 20,.....,9, 18

(1) 1 (2) 3 (3) 4 (4) 5 (5) 6

Sol. 8, 6, 24/7, 3, 21/5, 4, 20/_, 9, 18

Third number in each part is LCM of first two

numbers. Thus, the answer should be 6.

3. 8, 4, 4, 7, 8, 1, 3, 9, 3, 2, 1,....

(1) 1 (2) 2 (3) 3 (4) 5 (5) N.O.T

Sol. 8, 4, 4/7, 8, 1/3, 9, 3/2, 1...

In each part, third number is HCF of first to

numbers. Thus our answer should be 1.

IV. Some numbers followed by their product

1. 2, 3, 6, 18, 108, 1844

Which of the above numbers does not fit into

the series?

Sol. 1844 is wrong, because

2 × 3 = 6, 3 × 6 = 18, 18 × 6 = 108,

but 108 × 18 = 1944.

V. By use of digit-sum

1. 14, 19, 29, 40, 44, 51, 59, 73

Which of the above numbers doesn't fit into

the series ?

Sol. Next number = Previous number + Digit-sum

of previous number Like,

19 = 14 + (4 + 1)

29 = 19 + (1 + 9)

40 = 29 + (2 + 9)

Thus, we see that 51 should be replaced by

52.

2. Fill up the blanks

14, 5, 18, 9, 22, 4, 26, 8, 30, 3, ....., .....

Sol. 1st, 3rd, 5th, 7th, ... numbers follow the

pattern of +4 (14 + 4 = 18, 18 + 4 = 22,...).

Where as 2nd, 4th, 6th are the digit-sums of

their respective previous number (5 = 1 + 4, 9

= 1 + 8),...) Thus, our answer is 34 and 7.

VI. Odd number out

Sometimes a group of numbers is written out

of which one is different from others.

1. 22, 44, 88, 132, 165, 191, 242. Find the

number which doesn't fit in the above series

(or group).

Sol. 191; Others are divisible by 11 or 191 is the

single prime number.

2. Which one of the following series doesn't fit

into the series ?

29, 31, 37, 43, 47, 51, 53

Sol. 51; All other are prime numbers.

Two-line Number Series

Now a days this type of number series is also

being asked in examinations.

In this type of no. series one complete series

is given while the other is incomplete. Both

the series have the same definite rule.

Applying the very definite rule of the

complete series, you have to determine the

required no. of the incomplete series. For

example:

Ex.21 4 14 36 114 460

2 a b c d e

Find the value of e.

Sol. The first series is ×1 + 10, ×2 +8, ×3 +6, ×4 +

4,.....

a = 2 × 1 + 10 = 12, b = 12 × 2 + 8 = 32,

c = 32 × 3 + 6 = 102, d = 102 × 4 + 4 = 412,

and finally e = 412 × 5 + 2 = 2062

Ex.22 5 6 11 28 71 160

2 3 a b c d e

What is the value of e?

Sol. The differences of two successive terms of the

first series are 1, 5, 17, 43, 89, the sequence

of which is 03 + 12, 13 + 22, 23 + 32, 33 + 42,

43 + 52.

a = 3 + 5 = 8, b = 8 + 17 = 25, c = 25 + 43

= 68, d = 68 + 89 = 157, and finally

e = 157 + (53 + 62

= 125 + 36 =) 161 = 318

TRIVENI NTSE PROGRAM Number Series 8

8 8

Ex.23 1296 864 576 384 256

1080 a b c d e

What should replace c ?

Sol. The first series is ÷ 3 × 2

a = 1080 ÷ 3 × 2 = 720, b = 720 ÷ 3 × 2=480,

and finally c = 480 ÷ 3 × 2 = 320

Ex.24 7 13 78 83 415

3 a b c d e

Find the value of b.

Sol. The first series is +6, ×6, +5, ×5

a = 3 + 6 = 9 and b = 9 × 6 = 54

Ex.25 3240 540 108 27 9

3720 a b c d e

What is the value of d?

Sol. The first series is ÷ 6, ÷ 5, ÷ 4, ÷ 3

a = 3720 ÷ 6 = 620, b = 620 ÷ 5 = 124, c =

124 ÷ 4 = 31, and finally d = 31 ÷ 3 = 10.33

Ex.26 27 44 71 108 155

34 a b c d e

What is the should replace e?

Sol. The differences of two successive terms of

the series are 17, 27, 37, 47.

a = 34 + 17 = 51, b = 51 + 27 = 78,

c = 78 + 37 = 115, d = 115 + 47 = 162, and

finally e = 162 + 57 = 219

Ex.27. 108 52 24 10 3

64 a b c d e

What is the value of c ?

Sol. The series is –4 ÷ 2

a = (64 – 4) ÷ 2 = 30, b =(30 – 4) ÷ 2 = 13,

c = (13 – 4) ÷ 2 = 4.5

Ex.28 –4 –2 –1 8 31

–1 a b c d e

Find the value of b.

Sol. The series is repeated as ×2 + 6 and

× 3 + 7 alternately.

a = –1 × 2 + 6 = 4 and b = 4 × 3 + 7 = 19

Ex.29 5 8 41 33 57 42 61

3 4 a b c d e

Find the value of d.

Sol. This is an alternate number series having two

series :

S1 = 5 41 57 61.

The differences between two successive terms

are 36 (= 62), 16 (= 42), 4( = 22) and

S2 = 8 33 42

The differences between two successive terms

are 25 (= 52), 9 (= 32)

b = 4 + 25 = 29 and d = 29 + 9 = 38.

Ex.30 Find the wrong number in the series :

7, 28, 63, 124, 215, 342, 511

(A) 7 (B) 28 (C) 124 (D) 215

Sol. Clearly, the correct sequence is

23 – 1, 33 – 1, 43 – 1, 53 – 1, 63 – 1, 73 – 1,

83–1

28 is wrong and should be replaced by

(33 – 1) i.e. 26.

Hence, the answer is (B).

Ex.31 Find the wrong number in the series :

3, 8, 15, 24, 34, 48, 63

(A) 15 (B) 24 (C) 34 (D) 48

Sol. The difference between consecutive terms of

the given series are respectively 5, 7, 9, 11

and 13.

Clearly, 34 is a wrong number and must be

replaced by (24 + 11) i.e. 35.

Hence, the answer is (C).

Ex.32 24, 27, 31, 33, 36

(A) 24 (B) 27 (C) 31 (D) 33

Sol. Each term in the series is increased by 3 to

obtain the next term.

So, 31 is wrong and must be replaced by

(27 + 3) i.e. 30.

Ex.33 196, 169, 144, 121, 80

(A) 80 (B) 121 (C) 169 (D) 196

Sol. The sequence is (14)2, (13)2, (12)2, (11)2,

(10)2.

So, 80 is wrong and must be replaced by (10)2

i.e. 100.

TRIVENI NTSE PROGRAM Number Series 9

9 9

Ex.34 3, 5, 7, 9, 11, 13

(A) 3 (B) 5 (C) 7 (D) 9

Sol. The series consists of consecutive prime

numbers. So, 9 is wrong.

Ex.35 121, 143, 165, 186, 209

(A) 143 (B) 165 (C) 186 (D) 209

Sol. Each term of the series is increased by 22 to

obtain the next term.

So, 186 is wrong and must be replaced by

(165 + 22) i.e. 187.

Ex.36 1, 2, 4, 8, 16, 32, 64, 96

(A) 4 (B) 32 (C) 64 (D) 96

Sol. Each term of the series is obtained by

multiplying the preceding term by 2

So, 96 is wrong and must be replaced by

(64 × 2) i.e. 128.

Ex.37 8, 14, 26, 48, 98, 194, 386

(A) 14 (B) 48 (C) 98 (D) 194

Sol. Each term in the series is less than twice the

preceding term by 2.

So, 48 is wrong and should be replaced by

(26 × 2 – 2) i.e. 50.

Ex.38 8, 13, 21, 32, 47, 63, 83

(A) 13 (B) 21 (C) 32 (D) 47

Sol. The sequence is + 5, + 8, +11, ...

47 is wrong and must be replaced by

(32 + 14) i.e. 46.

Ex.39 3, 10, 27, 4, 16, 64, 5, 25, 125

(A) 3 (B) 4 (C) 10 (D) 27

Sol. The correct sequence is

3, 32, 33, 4, 42, 43, 5, 52, 53.

So, 10 is wrong and must be replaced by 32

i.e. 9.

TRIVENI NTSE PROGRAM Number Series 10

10 10

EXERCISE

Q.1 3, 15, 35, ...., 99, 143.

(A) 63 (B) 69 (C) 77 (D) 81

Q.2 5, 11, 17, ...., 29, 41.

(A) 19 (B) 21 (C) 23 (D) 25

Q.3 7, 17, 31, 49 ...., 97, 127

(A) 59 (B) 61 (C) 71 (D) 87

Q.4 1, 3, 6, 10, 15 ...., 28, 36.

(A) 20 (B) 21 (C) 23 (D) 24

Q.5 2, 5, 9, ....., 20, 27

(A) 14 (B) 15 (C) 16 (D) 17

Q.6 0, 2, 8, 14, 24, 34, ...., 62.

(A) 40 (B) 42 (C) 48 (D) 52

Q.7 4, 9, 20, 37, 60,....

(A) 88 (B) 89 (C) 90 (D) 91

Q.8 1, 3, 3, 6, 7, 9 ...., 12, 21

(A) 10 (B) 11 (C) 12 (D) 13

Q.9 8, 10, 14, 18, ...., 34, 50, 66

(A) 28 (B) 27 (C) 26 (D) 25

Q.10 19, 2, 38, 3, 114, 4, ....

(A) 228 (B) 256 (C) 352 (D) 456

Q.11 4, 9, 17, 35, ...., 139.

(A) 89 (B) 79 (C) 69 (D) 59

Q.12 7, 15, 32, ...., 138, 281.

(A) 57 (B) 67 (C) 77 (D) 87

Q.13 8, 12, 10, 16, 12, ....

(A) 20 (B) 18 (C) 16 (D) 14

Q.14 10, 2, 20, 3, 30, 4, ....

(A) 40 (B) 50 (C) 60 (D) 70

Q.15 24, 6, 48, 12, 96, 24 .....

(A) 191 (B) 192 (C) 193 (D) 194

Q.16 3, 10, 18, 27, 37, 48, .....

(A) 60 (B) 70 (C) 80 (D) 90

Q.17 1, 3, 9, 27, 81, 243, ........

(A) 729 (B) 730 (C) 731 (D) 732

Q.18 10, 7, 6, 8, 5, 4, ....

(A) 4 (B) 5 (C) 6 (D) 7

Q.19 5, 2, 6, 2, 7, 2, .....

(A) 8 (B) 9 (C) 10 (D) 11

Q.20 4, 8, 16, 32, 64, 128 .....

(A) 256 (B) 257 (C) 258 (D) 259

Q.21 0.5, 1.5, 4.5, 13.5, (.....)

(A) 45.5 (B) 39.5 (C) 30.5 (D) 40.5

Q.22 121, 225, 361, (.....)

(A) 441 (B) 484 (C) 529 (D) 729

Q.23 0, 2, 8, 14, (.....), 34

(A) 24 (B) 22 (C) 20 (D) 18

Q.24 19, 2, 38, 3, 114, 4, (.....)

(A) 228 (B) 256 (C) 352 (D) 456

Q.25 1, 2, 3, 6, 9, 18, (.....), 54

(A) 18 (B) 27 (C) 36 (D) 81

Q.26 4, 5, 9, 18, 34, (.....)

(A) 43 (B) 49 (C) 50 (D) 59

Q.27 3, 6, 18, 72, (.....)

(A) 144 (B) 216 (C) 288 (D) 360

Q.28 66, 36, 18, (.....)

(A) 3 (B) 6 (C) 8 (D) 9

Q.29 21, 25, 33, 49, 81, (.....)

(A) 145 (B) 129 (C) 113 (D) 97

Q.30 12, 32, 72, 152, (.....)

(A) 312 (B) 325 (C) 515 (D) 613

Q.31 3, 6, 5, 20, 7, 42, 9, (.....)

(A) 54 (B) 60 (C) 66 (D) 72

Q.32 1, 3, 4, 8, 15, 27, (.....)

(A) 37 (B) 44 (C) 50 (D) 55

Q.33 2, 15, 41, 80, (.....)

(A) 111 (B) 120 (C) 121 (D) 132

Q.34 8, 10, 14, 18, (.....), 34, 50, 66

(A) 24 (B) 25 (C) 26 (D) 27

Q.35 1, 2, 6, 24, (.....)

(A) 60 (B) 95 (C) 120 (D) 150

Q.36 2, 3, 8, 63, (.....)

(A) 1038 (B) 1998 (C) 3008 (D) 3968

Q.37 95, 115.5, 138, (.....), 189

(A) 154.5 (B) 162.5 (C) 164.5 (D) 166.5

Q.38 4, 10, (.....), 82, 244, 730

(A) 24 (B) 28 (C) 77 (D) 218

Q.39 4, 32, 128, (.....)

(A) 128 (B) 144 (C) 192 (D) 256

Q.40 2, 5, 9, 19, 37, (.....)

(A) 76 (B) 75 (C) 74 (D) 72

Q.41 24, 60, 120, 210, (.....)

(A) 300 (B) 336 (C) 420 (D) 525

Q.42 165, 195, 255, 285, 345, (.....)

(A) 375 (B) 420 (C) 435 (D) 390

TRIVENI NTSE PROGRAM Number Series 11

11 11

Q.43 5, 17, 37, 65, (.....), 145

(A) 95 (B) 97 (C) 99 (D) 101

Q.44 9, 11, 20, 31, (.....), 82

(A) 41 (B) 51 (C) 60 (D) 71

Q.45 5, 16, 49, 104, (.....)

(A) 115 (B) 148 (C) 170 (D) 181

Q.46 34, 18, 10, 6, 4, (.....)

(A) 0 (B) 1 (C) 2 (D) 3

Q.47 462, 420, 380, (.....), 306

(A) 322 (B) 332 (C) 342 (D) 352

Q.48 3, 8, 22, 63, 185, (.....)

(A) 550 (B) 310 (C) 295 (D) 285

Q.49 1, 2, 5, 12, 27, 58, 121, (.....)

(A) 246 (B) 247 (C) 248 (D) 249

Q.50 0.5, 0.55, 0.65, 0.8, (.....)

(A) 0.9 (B) 0.82 (C) 1 (D) 0.95

Directions :

In each of the following questions, one term in the

number series is wrong. Find out the wrong term.

Q.51 380, 188, 92, 48, 20, 8, 2

(A) 188 (B) 92 (C) 48 (D) 20

Q.52 1, 3, 7, 15, 27, 63, 127

(A) 7 (B) 15 (C) 27 (D) 63

Q.53 5, 10, 17, 24, 37

(A) 10 (B) 17 (C) 24 (D) 37

Q.54 1, 3, 10, 21, 64, 129, 256, 778

(A) 10 (B) 21 (C) 129 (D) 256

Q.55 15, 16, 22, 29, 45, 70

(A) 16 (B) 22 (C) 45 (D) 70

Q.56 6, 14, 30, 64, 126

(A) 6 (B) 14 (C) 64 (D) 126

Q.57 10, 26, 74, 218, 654, 1946, 5834

(A) 26 (B) 74 (C) 218 (D) 654

Q.58 3, 7, 15, 39, 63, 127, 255, 511

(A) 15 (B) 39 (C) 63 (D) 127

Q.59 445, 221, 109, 46, 25, 11, 4

(A) 25 (B) 46 (C) 109 (D) 221

Q.60 1236, 2346, 3456, 4566, 5686

(A) 1236 (B) 3456 (C) 4566 (D) 5686

Q.61 5, 10, 40, 80, 320, 550, 2560

(A) 80 (B) 320 (C) 550 (D) 2560

Q.62 3, 2, 8, 9, 13, 22, 18, 32, 23, 42

(A) 8 (B) 9 (C) 13 (D) 22

Q.63 8, 27, 125, 343, 1331

(A) 8 (B) 343 (C) 1331 (D) None

Q.64 10, 14, 28, 32, 64, 68, 132

(A) 28 (B) 32 (C) 64 (D) 132

Q.65 1, 5, 5, 9, 7, 11, 11, 15, 12, 17

(A) 11 (B) 12 (C) 17 (D) 15

Q.66 11, 2, 21, 3, 32, 4, 41, 5, 51, 6

(A) 21 (B) 11 (C) 32 (D) 51

Q.67 11, 5, 20, 12, 40, 26, 74, 54

(A) 5 (B) 20 (C) 40 (D) 26

Q.68 56, 72, 90, 110, 132, 150

(A) 72 (B) 90 (C) 110 (D) 150

Q.69 8, 13, 21, 32, 47, 63, 83

(A) 13 (B) 32 (C) 47 (D) 63

Q.70 89, 78, 86, 80, 85, 82, 83

(A) 83 (B) 82 (C) 86 (D) 78

Q.71 25, 36, 49, 81, 121, 169, 225

(A) 36 (B) 49 (C) 169 (D) 225

Q.72 2, 5, 10, 17, 26, 37, 50, 64

(A) 17 (B) 26 (C) 37 (D) 64

Find the missing number in the following series

Q.73 4, 7, 11, 18, 29, 47, ....., 123, 199

(A) 76 (B) 70 (C) 84 (D) 102

Q.74 2, 6, 12, 20, ........, 42, 56, 72, 90

(A) 20 (B) 21 (C) 30 (D) 12

Q.75 17, 7, 24, 19, 9, 28, ...., 8, 31, 27, 10, 37

(A) 20 (B) 21 (C) 18 (D) 23

Q.76 6, 126,........, 9, 108, 12, 7, 133, 19, 12, 72, 6

(A) 21 (B) 23 (C) 30 (D) 35

Q.77 2, ...........8, 16, 32, 64, 128, 256

(A) 2 (B) 3 (C) 4 (D) 5

Q.78 45, 54, 47,......, 49, 56, 51, 57, 53

(A) 48 (B) 55 (C) 50 (D) 53

Q.79 3, 128, 6, 64, 9, ....., 12, 16, 15, 8

(A) 32 (B) 12 (C) 108 (D) 72

Q.80 5, 7, 11, 19, 35, 67, ...., 259

(A) 64 (B) 131 (C) 135 (D) 32

Q.81 8, 4, 12, 6, 18,......27

(A) 9 (B) 12 (C) 18 (D) 24

Q.82 16, 22, 34, 58, 106, ....., 394

(A) 178 (B) 175 (C) 288 (D) 202

Q.83 2, 3, 5, 9, 17, 33,......

(A) 85 (B) 37 (C) 63 (D) 65

TRIVENI NTSE PROGRAM Number Series 12

12 12

Q.84 2, 9, 23, 3, 8, 25, 4, ......, 27

(A) 7 (B) 29 (C) 23 (D) 14

Q.85 121, 112, ........, 97, 91, 86

(A) 102 (B) 108 (C) 99 (D) 104

Q.86 6, 9, 15, 27,.....,99

(A) 51 (B) 34 (C) 37 (D) 84

Q.87 4, 7, 12,......, 28, 39

(A) 19 (B) 24 (C) 14 (D) 16

Q.88 83, 82, 81, ....., 69, 60, 33

(A) 73 (B) 80 (C) 75 (D) 77

Q.89 77, 78, 77, 81, 73, ...., 55

(A) 69 (B) 71 (C) 82 (D) 89

Q.90 6, 7, 9, 13, 21,......

(A) 25 (B) 29 (C) 37 (D) 32

Q.91 11, 10, ......, 100, 1001, 1000, 10001

(A) 101 (B) 110 (C) 111 (D) None

Q.92 4, 8, 12, 24, 36, 72,......

(A) 108 (B) 98 (C) 92 (D) 96

Q.93 1, 2, 3, 5, 7,.....

(A) 8 (B) 9 (C) 10 (D) 13

Q.94 3, 6, 6, 12, 9,...........12

(A) 15 (B) 18 (C) 11 (D) 13

Directions (95 – 103) :

In each of the following questions, one number is

wrong in the series. Find out the wrong number :

Q.95 3, 5, 12, 39, 154, 772, 4634

(A) 5 (B) 3 (C) 39 (D) 154

(E) none of these

Q.96 376, 188, 88, 40, 16, 4, –2

(A) 4 (B) 16 (C) 40 (D) 188

(E) none of these

Q.97 444, 300, 200, 136, 87, 84, 80

(A) 200 (B) 136 (C) 87 (D) 80

(E) none of these

Q.98 2, 3, 12, 37, 86, 166, 288

(A) 2 (B) 3 (C) 166 (D) 86

(E) 37

Q.99 4, 9, 19, 43, 90, 185, 375

(A) 9 (B) 19 (C)90 (D) 185

(E) none of these

Q.100 572, 284, 140, 72, 32, 14, 5

(A) 14 (B) 32 (C) 72 (D) 5

(E) 140

Q.101 4, 10, 23, 50, 104, 216, 439

(A) 4 (B) 10 (C) 23 (D) 104

(E) 216

Q.102 701, 348, 173, 85, 41, 19, 8

(A) 173 (B) 41 (C) 19 (D) 8

(E) 348

Q.103 2, 3, 9, 27, 112, 565, 3396

(A) 565 (B) 9 (C) 112 (D) 27

(E) 3396

Direction :

In the following number series, one of the numbers

does not fit into the series. Find the wrong number.

Q.104 1788, 892, 444, 220, 112, 52, 24

(A) 52 (B) 112 (C) 220 (D) 444

(E) 892

Q.105 225, 289, 398, 374, 397, 415, 424

(A) 415 (B) 289 (C) 338 (D) 374

(E) 397

Q.106 5, 7.5, 11.25, 17.5, 29.75, 50, 91.25

(A) 7.5 (B) 17.5 (C) 29.75 (D) 91.25

(E) None of these

Q.107 35, 118, 280, 600, 1238, 2504, 5036

(A) 118 (B) 280 (C) 600 (D) 1238

(E) 2504

Q.108 10, 12, 28, 90, 368, 1840, 11112

(A) 1840 (B) 368 (C) 90 (D) 28

(E) 12

Directions :

In each of the following one number is wrong in the

series. Find out the wrong number in each case

Q.109 1, 2, 5, 14, 41, 124

(A) 2 (B) 5 (C) 14 (D) 41

(E) 124

Q.110 100, 97, 90, 86, 76, 71, 62, 55

(A) 55 (B) 62 (C) 76 (D) 86

(E) 97

Q.111 1, 2, 6, 24, 120, 620, 5040

(A) 5040 (B) 620 (C) 120 (D) 24

(E) 6

Q.112 4, 10, 22, 40, 64, 84, 130

(A) 22 (B) 40 (C) 64 (D) 84

(E) 130

Q.113 1, 4, 8, 16, 31, 64, 127, 256

(A) 31 (B) 16 (C) 8 (D) 6

(E) 1

Q.114 49, 56, 64, 71, 81, 90, 100, 110

(A) 56 (B) 64 (C) 71 (D) 81

(E) 90

TRIVENI NTSE PROGRAM Number Series 13

13 13

Directions (115- 119) :

In each questions given below, Four out of the five

given sets of numbers follow the same pattern, while

the fifth one is different. You have to find out the set

that does not match with others.

Q.115 (A) 3 (58) 7 (B) 1 (10) 3

(C) 2 (20) 4 (D) 5 (51) 6

(E) 8(145) 9

Q.116 (A) 4(36)2 (B) 10(102)1

(C) 6 (121)5 (D) 3(49) 4

(E) 7(225) 8

Q.117 (A) 8(39)5 (B) 12(44)10

(C) 7(48) 1 (D) 9(45)6

(E) 5(17)2

Q.118 (A) 5(68)9 (B) 11(8)13

(C) 3(27)6 (D) 7(125)12

(E) 6(64)10

Directions (119- 128) :

In each of the following questions, a number series is

given. After the series , below it in the next line, a

number is given followed by (A), (B), (C), (D) and

(E). You have to complete the series starting with the

number given following sequence of the given series.

Then, answer the questions given below it.

Q.119 535, 366, 245, 164,

817 , (a), (b), (c), (d), (e)

Which of the following numbers will come in

place of (e) ?

(A) 648 (B) 507 (C) 387 (D) 372

(E) none of these

Q.120 3, 5, 18, 72,

7 , (a), (b), (c), (d), (e)

Which of the following numbers will come in

place of (d) ?

(A) 416 (B) 9 (C) 2100 (D) 96

(E) none of these

Q.121 2, 9, 57, 337,

3, (a), (b), (c), (d), (e)

Which of the following numbers will come in

place of (b) ?

(A) 113 (B) 17 (C) 3912 (D) 8065

(E) none of these

Q.122 15, 159, 259, 323,

7, (a), (b), (c), (d), (e)

Which of the following numbers will come in

place of (c) ?

(A) 251 (B) 315 (C) 176 (D) 151

(E) none of these

Q.123 288, 140, 66, 29,

488, (a), (b), (c), (d), (e)

Which of the following numbers will come in

place of (e) ?

(A) 106 (B) 18.5 (C) 49 (D) 6.25

(E) none of these

Q.124 140, 68, 36, 16, 10 3

284, (a), (b), (c), (d), (e)

Which of the following numbers will come in

place of (b) ?

(A) 38 (B) 72 (C) 84 (D) 91

(E) none of these

Q.125 25, 194, 73, 154,

105

14, (a), (b), (c), (d), (e)

Which of the following numbers will come in

place of (d) ?

(A) 90 (B) 84 (C) 102 (D) 94

(E) none of these

Q.126 6, 9, 18, 45, 135

20, (a), (b), (c), (d), (e)

Which of the following numbers will come in

place of (c) ?

(A) 324 (B) 81 (C) 175 (D) 150

(E) 216

Q.127 2 9 57 337 1681

3 (a), (b), (c), (d), (e)

Which of the following numbers will come in

place of (e) ?

(A) 32416 (B) 4231 (C) 13441 (D) 6392

(E) none of these

Q.128 3, 4, 10, 33, 136

7, (a), (b), (c), (d), (e)

Which of the following numbers will come in

place of (e) ?

(A) 1035 (B) 1165 (C) 1039 (D) 891

(E) none of these

Directions (129- 137) :

Each of the following questions consists of a pair of

numbers that have a certain relationship to each other,

followed by four other pairs of numbers given as

alternatives. Select the pair in which the numbers are

similarly related as in the given pair.

Q.129 27 : 9

(A) 64 : 9 (B) 125 : 5

(C) 135 : 15 (D) 729 : 81

TRIVENI NTSE PROGRAM Number Series 14

14 14

Q.130 11 : 1210

(A) 6 : 216 (B) 7 : 1029

(C) 8 : 448 (D) 9 : 729

Q.131 Find a group similar to (3, 7, 11).

(A) 2, 9, 21 (B) 2, 17, 23

(C) 4, 6 , 14 (D) 7, 9, 16

Q.132 Given set : (49, 25, 9)

(A) (36, 16, 4) (B) (36, 25, 16)

(C) (39, 26, 13) (D) (64, 27, 8)

Q.133 Given set : (21, 51, 15)

(A) (21, 30, 51) (B) (21, 35, 41)

(C) (21, 51, 42) (D) (21, 91, 35)

Q.134 Given set : (9, 15, 21)

(A) (10, 14, 16) (B) (7, 21, 28)

(C) (5, 10, 25) (D) (4, 8, 12)

Q.135 11 : 17 : : 19 : ?

(A) 23 (B) 27 (C) 33 (D) 21

Q.136 Which number is the given set of numbers ?

Given set : (3, 17, 31)

(A) 5 (B) 15 (C) 45 (D) 49

Q.137 As 425 is related to 2, in the same way 613 is

related to -

(A) 1 (B) 2 (C) 3 (D) 4

Directions (138- 142) :

Find the missing term of the pair

Q.138 7528 : 5362 : : 4673 : ?

(A) 2367 (B) 2451 (C) 2531 (D) 2617

(E) None of these

Q.139 9 : 9 : : 8 : ?

(A) 14 (B) 64 (C) 25 (D) 27

(E) 20

Q.140 6 : 24 : : 5 : ?

(A) 23 (B) 22 (C) 25 (D) 27

(E) 20

Q.141 25 : 125 : : 36 : ?

(A) 180 (B) 206 (C) 216 (D) 318

(E) 72

Q.142 3 : 7 : : 08 : ?

(A) 10 (B) 13 (C) 17 (D) 14

(E) 16

TRIVENI NTSE PROGRAM Number Series 15

15 15

ANSWER KEY

EXERCISE-1

HINTS & SOLUTIONS

1. 22 – 1, 42 – 1, 62 – 1

2. +6, +6, +6 ...

3. +10, +14, ...

8. Ist series = 1, 3, 7 .... 21

IInd series = 3, 6, 9, 12

The pattern is Ist series is +2, +4, ...

missing number = 7 + 6 = 13

10. Ist series 19, 38, 114, ......

IInd series 2, 3, 4 .....

The pattern followed in Ist is ×2, ×3 ....

missing number = 114 × 4 = 456

11. 4 × 2 + 1, 9 × 2 – 1, ...

14. 10 × 2 = 20, 10 × 3 = 30 ....

21. Each term of the series is obtained by

multiplying the preceding term by 3.

Missing number = 13. 5 × 3 = 40.5.

22. The numbers are 112, 152, 192,... i.e. 112

(11 + 4 × 1)2, (11 + 4 × 2)2, ...

Missing number = (11 + 4 × 3)2

= (23)2 = 529.

23. The numbers are

12 – 1, 22 – 2, 32 – 1, 42 – 2....

Missing number = 52 – 1 = 24.

24. The sequence is a combination of two series:

I. 19, 38, 114, (...) and II. 2, 3, 4

The pattern followed in I is ×2, ×3, ...

Missing number = 144 × 4 = 456.

25. The numbers are alternately multiplied by 2

and . Thus, 1 × 2 = 2, 2 × = 3, 3 × 2 = 6,

6 × = 9 and so on.

Missing number = 18 × = 27.

26. The pattern is +1, +4, + 9, + 16,... i.e.,

+ 12, + 22, + 32, 42, ....

Missing number = 34 + 52 = 34 + 25 = 59.

27. The pattern is ×2, ×3, ×4, ...

Missing number = 72 × 5 = 360.

28. Each number in the series is the product of

the digits of the preceding number.

Thus, 6 × 6 = 36, 3 × 6 = 18 and so on.

Missing number = 1 × 8 = 8.

29. The pattern is +4, +8, +16, +32, ... i.e., + 22, +

23, + 24, + 25,...

Missing number = 81 + 26 = 81 + 64=145.

30. The pattern is +20, +40, +80,...

Missing number = 152 + 160 = 312.

Q.No 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

Ans. A C C B A C B D C D C B A A B A A C A A

Q.No 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40

Ans. D C A D B D D C A A D C D C C D B B D B

Q.No 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60

Ans. B C D B D D C A C C C C C D B C D B B D

Q.No 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80

Ans. C B D D B C C D C C A D A C D A C B A B

Q.No 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100

Ans. A D D A D A A D C C A A C B C D C C B C

Q.No 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120

Ans. D E B B E C D A E A B D C C D B E A D A

Q.No 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140

Ans. A B D B D D C B D C B A D D C A A B C E

Q.No 141 142

Ans. C C

2

3

2

3

2

3

2

3

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